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HARDMCQ SINGLEJEE Advanced ChemistryOrganic ChemistryHydrocarbonsAchiever Section

Match the column I with column II and mark the appropriate choice. Column I Column II (A) n-butane 2-methylpropane (i) Free radical substitution (B) hv CH Cl CH Cl → (ii) Wurtz reaction (C) RCOONa + soda lime RH (iii) Isomerisation (D) ether RX Na R R → (iv) Decarboxylatio n

A.(A) → (iii), (B) → (i), (C) → (iv), (D) → (ii)✓ Correct
B.(A) → (ii), (B) → (iv), (C) → (i), (D) → (iii)
C.(A) → (i), (B) → (ii), (C) → (iv), (D) → (iii)
D.(A) → (iv), (B) → (i), (C) → (iii), (D) → (ii)
Explanation

In A, the number of carbons and hydrogens present in reactant and product are same. Therefore, it refers to isomerisation. In B, methane on reaction with chlorine in the presence of sunlight gives the chloro-substituted product by free radical substitution. In C, Soda lime is the mixture of NaOH and CaO. The given reaction is decarboxylation reaction. 2 lim RCOOH Soda e RH CO → This means that the number of carbon is reduced in decarboxylation reaction. In D, Wurtz reaction, two molecules of alkyl halides combine to produce higher alkanes. Since it contains two number of carbon atoms.

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