HARDMCQ SINGLEJEE Mains ChemistryPhysical ChemistryGaseous stateAchiever Section
X ml of H₂ gas effuses through a hole in a container in 5 seconds. The time taken for the effusion of the same volume of the gas specified below under identical condition is
A.10 seconds : He
B.20 seconds : O₂✓ Correct
C.25 seconds : CO
D.55 seconds : CO₂
Explanation
Rate of diffusion = Volume diffused time taken 1 1 1 2 2 2 2 1 1 2 v r t t M v r t M t (a) 10 seconds: He 10 4 5 2 (b) 2 20 seconds : O 20 32 5 2 (c) 25 seconds : CO 25 28 5 2 (d) 2 55 seconds : CO 55 44 5 2 Thus, the correct answer is (b)
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