Calculate the number of moles in the glass bulb shown in figure at 300 K. Given : density of glycerine = 2.72 g/mL; density of mercury = 13.6g/mL

gas atm gh P = P gly h = 5 m If glycerine is replaced by Hg gly gly Hg Hg = h h gly gly Hg Hg h 2.72 h 5=1m 13.6 >> x gas gas P = 76 cm + 100 cm=176cm P 176 1760 1 760 Hg 1760 176 1760 mm Hg= 760 76 cm mm atm mm >> >> 176 P = atm, 76 v = 10 lt, T = 300K 176 10 PV 76 0.94 moles RT 0.0821 300 n x x