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Two students use same stock solution of ZnSO₄ but different solutions of CuSO₄. The EMF of one cell is 0.03 V higher than the other. The concentration of CuSO₄ in the cell with higher EMF value is 0.5 M. The concentration of CuSO₄ in the other cell is (2.303 RT/F = 0.06)

A.0.05 M
B.5.0 M
C.0.5 M✓ Correct
D.0.005 M
Explanation

10. We have an oxidation-reduction system: [Fe(CN)₆]3– + e– ⇌ [Fe(CN)₆]4–; Eo = +0.36 V. The ratio of concentrations of oxidized and reduced from at which the potential of the system becomes 0.24 V, is [Given: 2.303 RT/F = 0.06] (a) 2:1 (b) 1:2 (c) 1:20 (d) 1:100 Given, [Fe(CN)₆]3– + e– ⇌ [Fe(CN)₆]4–; Eo = +0.36 V. The ratio of oxidised form to reduced form is. 11. A hydrogen electrode is immersed in a solution with pH = 0 (HCl). By how much will the potential (reductin) change if an equivalent amount of NaOH is added to the solution. (Take PH₂ = 1 atm), T = 298 K. (a) increase by 0.41 V (b) i

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