HARDMCQ SINGLEJEE Advanced ChemistryPhysical ChemistryElectrochemistryAchiever Section
The e.m.f. of a Daniell cell at 298K is When the concentration of ZnSO₄ is 1.0 M and that of CuSO₄ is 0.01 M, the e.m.f. changed to E2. What is the relationship between E1 and E2?
A.E1< E2
B.E1 = E2
C.E2 = 0 ≠ E1
D.E1> E2✓ Correct
Explanation
From the Nernst’s equation, Putting the given concentration of the ions, it can be written that- Similarly, ELECTROCHEMISTRY 42 E1 > E2 Therefore, the correct answer is option (d)
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