For the square planar complex [M (a) (b) (c) (d)] (where, M = central metal and a, b, c and d are monodentate ligands), the number of possible geometrical isomers are

For the square planar complex [Mabcd] where M is the central atom and a,b,c,d are monodentate ligands, the number of possible geometrical isomers are three. In isomer I, C is opposite to A. In isomer II, D is opposite to A. In isomer III, B is opposite to A. Hence, option (c) is the correct answer