What is (are) number(s) of unpaired electrons in the square planar [Pt(CN)₄]2– ion?

As in the compound a strong ligand is present Hence, it will have a hybridization of 2 dsp Hence, the unpaired electrons in 5d orbital pair up to make one d orbital empty for dsp2 hybridization. Thus, there is no unpaired electron. Hence, the correct option is (a).