0 2.303log >> T P kt P 2 2 2 2 0 0 Initial 0 0 At t=100 p T SO Cl SO Cl P P p p P → After time, t, total pressure, ( ) T o P P p p p ( ) ( ) 2 T o T o o o T o o T P P p p P P P p P P P P P >> >> Using, Integrated rate law, 0 3 1 2.303log 2 2.303 0.5 log 100 0.4 2.303 log1.25 100 2.303 0.097 100 2.23 10 x x x x o t P kt P P kt s Now, When total pressure = 0.65 2 2 2 2 0.5 0.65 0.35atm SO Cl o T P P P x Thus, reaction rate = 2 2 SO Cl kP 3 4 1 2.23 10 0.35 7.8 10 atm s x x x
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