Total pressure P 1 atm 3 2 n 1 n 4 3 2 n Initial and eqn. CaCO s CaO s CO intially 0atm 0 0 at eq 0 0 x k x P(Totalpressure) 1atm at eq NH HS s NH g H S g 0 0 0 at eq 0 x atm x atm Total pressure = x x 2x P P x 2 Hence 2 2 P 1 K x. x 4 4 2 4 3 2 n NH COONH (s) 2NH g CO (g) 0 0 0 at eq 0 2x x Total pressure 3x P P x 3 Hence 2 2 3 2P P K 2x x 3 3 x 3 4P 4 27 27 Hence 1 2 3 K K K correct answer (c) 12. Consider the equilibrium 2 2 1 CO CO(g) O (g) 2 The equilibrium constant K is given by (when <<< 1)
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