HARDMCQ SINGLENEET ChemistryInorganic ChemistryCarboxylic Acids and DerivativesAchiever Section

Acetamide is treated separately with the following reagents. Which one of these would give methyl amine?

A.PCl₅

B.NaOH + Br₂✓ Correct

C.Sodalime

D.Hot conc. H₂SO₄

Explanation

The reagent used in the conversion of 2 CONH functional group to 2 NH functional group is 2 NaOH Br It converts acetamide to methylamine. It is actually Hoffmann Bromamide degradation reaction. The reaction is given as- 3 2 2 3 2 2 3 2 CH CONH NaOH Br CH NH NaBr Na CO H O → Thus, the correct option is (b) 2 NaOH Br

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