HARDMCQ SINGLEJEE Mains ChemistryInorganic ChemistryCarboxylic Acids and DerivativesAchiever Section
Acetamide is treated separately with the following reagents. Which one of these would give methyl amine?
A.PCl₅
B.NaOH + Br₂✓ Correct
C.Sodalime
D.Hot conc. H₂SO₄
Explanation
The reagent used in the conversion of 2 CONH functional group to 2 NH functional group is 2 NaOH Br It converts acetamide to methylamine. It is actually Hoffmann Bromamide degradation reaction. The reaction is given as- 3 2 2 3 2 2 3 2 CH CONH NaOH Br CH NH NaBr Na CO H O → Thus, the correct option is (b) 2 NaOH Br
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