The saccharides which reduce the Fehling’s solution and Tollens’s reagent are called as the reducing sugar. Maltose is a reducing sugar because in one of the monosaccharides unit there is a hemiacetal group that can be opened to give the free -CHO group. On hydrolysis, it gives two moles of - D-glucose. It is composed of the two -D-glucose units together through 1 C of one unit and 4 C of the other unit. The maltose has a 1, 4- - glycosidic linkage. So, the assertion is true but the reason is incorrect. Thus, (c) is the correct option.
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