n = 10⁻⁴ × 6.023×10²³ = 6.023×10¹⁹ atoms. E = nhc/λ = (6.023×10¹⁹ × 6.626×10⁻³⁴ × 3×10⁸) / (5890×10⁻¹⁰) = 0.02031 kJ = 2.03×10⁻² kJ
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