MEDIUMMCQ SINGLEIChO (Chemistry Olympiad)Physical ChemistryAtomic StructureIntro
[NEET 2014] Calculate the energy in joule corresponding to light of wavelength 45 nm. (h = 6.63 × 10⁻³⁴ Js, c = 3 × 10⁸ ms⁻¹)
0.6.67 × 10⁻¹⁵ J
1.6.67 × 10⁻¹¹ J
2.4.42 × 10⁻¹⁵ J
3.4.42 × 10⁻¹⁸ J
Explanation
E = hc/λ = (6.63×10⁻³⁴ × 3×10⁸) / (45×10⁻⁹) = (1.989×10⁻²⁵) / (4.5×10⁻⁸) = 4.42×10⁻¹⁸ J
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