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HARDMCQ SINGLEIChO (Chemistry Olympiad)Physical ChemistryAtomic StructureIntro

[Kerala CEE 2014] The ratio of de Broglie wavelengths of a deuterium atom to that of an α-particle, when the velocity of deuterium is five times that of the α-particle, is

0.4
1.0.2
2.2
3.0.4
Explanation

λ = h/(mv). λ_D/λ_α = (m_α × v_α)/(m_D × v_D) = (4 × v_α)/(2 × 5v_α) = 4/10 = 0.4. (m_D = 2 u, m_α = 4 u; v_D = 5v_α)

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