MEDIUMMCQ SINGLENEET ChemistryPhysical ChemistryAtomic StructureIntro
[CBSE AIPMT 2011] The energies E₁ and E₂ of two radiations are 25 eV and 50 eV respectively. The relation between their wavelengths λ₁ and λ₂ will be
0.λ₁ = λ₂/2
1.λ₁ = λ₂
2.λ₁ = 2λ₂
3.λ₁ = 4λ₂
Explanation
E = hc/λ → λ ∝ 1/E. λ₁/λ₂ = E₂/E₁ = 50/25 = 2. So λ₁ = 2λ₂.
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