MEDIUMMCQ SINGLEJEE Mains ChemistryPhysical ChemistryAtomic StructureIntro

The ratio of the energy difference between the 1st and 2nd Bohr orbits to that between the 2nd and 3rd Bohr orbits is

0.1/2
1.1/3
2.27/5
3.4/9
Explanation

ΔE(1→2) = 13.6(1/1 − 1/4) = 13.6 × 3/4. ΔE(2→3) = 13.6(1/4 − 1/9) = 13.6 × 5/36. Ratio = (3/4)/(5/36) = (3/4) × (36/5) = 27/5.

Practice More Like This

Take chapter-wise tests, track your progress, and master Atomic Structure.

Start Free Practice →