n(n−1)/2 = 6 → n = 4. Minimum wavelength → maximum energy → transition from n=4 to n=1. 1/λ = R_H × Z² × (1/n₁² − 1/n₂²) = 4R_H(1 − 1/16) = 4R_H × 15/16. λ = 4/(15R_H)
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