For a 4d electron the orbital angular momentum is: ()

Question

**Options:**
- **A.** 
- **B.** 
- **C.** 
- **D.** zero

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**Difficulty:** MEDIUM | **Chapter:** Atomic Structure | **Topic:** Drawbacks of Bohr model, quantum model intro, quantum numbers

Accepted Answer

## ✅ Correct Answer: **A**

### 📖 Detailed Explanation:
**Solution:**

For a **4d electron:**
- n = 4
- l = 2 (d orbital)

**Orbital angular momentum:**
L = √(l(l+1)) × (h/2π)
L = √(2(2+1)) × (h/2π)
L = √6 × (h/2π)
L = **√6 ℏ** where ℏ = h/2π

**Answer: (A) √6 (h/2π)** or **√6 ℏ**

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Official Solution