A 1000 watt radio transmitter operates at a frequency of 880 kilocycle/sec. How many photons per sec does it emit?

## ✅ Correct Answer: **B** ### 📖 Detailed Explanation: **Solution:** **Given:** - Power P = 1000 W = 1000 J/s - Frequency ν = 880 kilocycles/sec = 880 × 10³ Hz **Energy of one photon:** E = hν = 6.626 × 10⁻³⁴ × 880 × 10³ E = 5.83 × 10⁻²⁸ J **Number of photons per second:** n = Total power / Energy per photon n = 1000 / (5.83 × 10⁻²⁸) n = **1.72 × 10³⁰ photons/sec** **Answer: (B) 1.72 × 10³⁰** --- *This is an official solution provided by Chem Mantra. For more chemistry questions and solutions, explore our [question bank](/courses).*