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A 2.00 g portion of a sample containing NaBr and was dissolved and diluted to 250 mL. One fifth aliquot portions were titrated by silver nitrate, an a...

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Mole conceptBasic stoichiometry, POAC, percent yield & limiting reagentHARDJEE Chemistry
A 2.00 g portion of a sample containing NaBr and was dissolved and diluted to 250 mL. One fifth aliquot portions were titrated by silver nitrate, an average of 42.5 mL solution being required for the aliquot portion. In standardization 1.00 mL is found to be equimolar to 0.0125 g KBr. Calculate percentage of Br in sample. **Options:** - **A.** [object Object] - **B.** [object Object] - **C.** [object Object] - **D.** [object Object] --- **Difficulty:** HARD | **Chapter:** Mole concept | **Topic:** Basic stoichiometry, POAC, percent yield & limiting reagent

Official Solution

## ✅ Correct Answer: **B** ### 📖 Detailed Explanation: This question uses volumetric analysis & stoichiometry. Relate mass, moles and number of particles using the mole concept and basic stoichiometry; doing the algebra gives the value listed in option B. --- *This is an official solution provided by Chem Mantra. For more chemistry questions and solutions, explore our [question bank](/courses).*

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Mole conceptBasic stoichiometry, POAC, percent yield & limiting reagentHARDJEE Chemistry