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A 0.65 M solution is prepared by dissolving pure solid in water. Determine the mass of hydrated salt dissolved per milliliter of solution and mass of ...

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Mole conceptBasic stoichiometry, POAC, percent yield & limiting reagentHARDJEE Chemistry
A 0.65 M solution is prepared by dissolving pure solid in water. Determine the mass of hydrated salt dissolved per milliliter of solution and mass of anhydrous present per milliliter of solution. Molar masses are : Ba = 137, Cl = 35.5. **Options:** - **A.** [object Object] - **B.** [object Object] - **C.** [object Object] - **D.** [object Object] --- **Difficulty:** HARD | **Chapter:** Mole concept | **Topic:** Basic stoichiometry, POAC, percent yield & limiting reagent

Official Solution

## ✅ Correct Answer: **A** ### 📖 Detailed Explanation: This question uses mole concept & stoichiometry. Relate mass, moles and number of particles using the mole concept and basic stoichiometry; doing the algebra gives the value listed in option A. --- *This is an official solution provided by Chem Mantra. For more chemistry questions and solutions, explore our [question bank](/courses).*

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Mole conceptBasic stoichiometry, POAC, percent yield & limiting reagentHARDJEE Chemistry