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On reduction with hydrogen, 3.6 g of an oxide of metal left 3.2 g of the metal. If the atomic weight of the metal is 64, the simplest formula of the o...

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Mole conceptLaw of chemical combination, atomic & molecular mass, mole concept, calculationsHARDJEE Chemistry
On reduction with hydrogen, 3.6 g of an oxide of metal left 3.2 g of the metal. If the atomic weight of the metal is 64, the simplest formula of the oxide would be **Options:** - **A.** [object Object] - **B.** [object Object] - **C.** [object Object] - **D.** [object Object] --- **Difficulty:** HARD | **Chapter:** Mole concept | **Topic:** Law of chemical combination, atomic & molecular mass, mole concept, calculations

Official Solution

## ✅ Correct Answer: **B** ### 📖 Detailed Explanation: This question uses atomic structure & atomic mass. Relate mass, moles and number of particles using the mole concept and basic stoichiometry; doing the algebra gives the value listed in option B. --- *This is an official solution provided by Chem Mantra. For more chemistry questions and solutions, explore our [question bank](/courses).*

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Mole conceptLaw of chemical combination, atomic & molecular mass, mole concept, calculationsHARDJEE Chemistry