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\(\mathrm{N_2}\) and \(\mathrm{H_2}\) are mixed in 14:3 mass ratio. After certain time ammonia was found to be 40% by mol. The mole fraction of \(\mat...

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Mole conceptBasic stoichiometry, POAC, percent yield & limiting reagentHARDJEE Chemistry
\(\mathrm{N_2}\) and \(\mathrm{H_2}\) are mixed in 14:3 mass ratio. After certain time ammonia was found to be 40% by mol. The mole fraction of \(\mathrm{N_2}\) at that time in the mixture of \(\mathrm{N_2}\) \(\mathrm{H_2}\) and \(\mathrm{NH_3}\) is **Options:** - **A.** [object Object] - **B.** [object Object] - **C.** [object Object] - **D.** [object Object] --- **Difficulty:** HARD | **Chapter:** Mole concept | **Topic:** Basic stoichiometry, POAC, percent yield & limiting reagent

Official Solution

## ✅ Correct Answer: **A** ### 📖 Detailed Explanation: This question uses concentration terms, stoichiometry and limiting reagent. Write the definition formula for the concentration term, substitute the given values, and solve for the unknown; the numerical value obtained corresponds to option A. --- *This is an official solution provided by Chem Mantra. For more chemistry questions and solutions, explore our [question bank](/courses).*

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Mole conceptBasic stoichiometry, POAC, percent yield & limiting reagentHARDJEE Chemistry