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6.023 ×1023 molecules of Ca (OH)2 react with 3.01×1022 molecules of HCl, number of moles of \(\mathrm{CaCl_2}\) obtained are

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Mole conceptBasic stoichiometry, POAC, percent yield & limiting reagentEASYJEE Chemistry
6.023 ×1023 molecules of Ca (OH)2 react with 3.01×1022 molecules of HCl, number of moles of \(\mathrm{CaCl_2}\) obtained are **Options:** - **A.** [object Object] - **B.** [object Object] - **C.** [object Object] - **D.** [object Object] --- **Difficulty:** EASY | **Chapter:** Mole concept | **Topic:** Basic stoichiometry, POAC, percent yield & limiting reagent

Official Solution

## ✅ Correct Answer: **C** ### 📖 Detailed Explanation: This question uses volumetric analysis & stoichiometry. Convert all given quantities into moles using n = given amount/molar mass, use Avogadro's number where needed to get particles, and then compare with the options; this matches option C. --- *This is an official solution provided by Chem Mantra. For more chemistry questions and solutions, explore our [question bank](/courses).*

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Mole conceptBasic stoichiometry, POAC, percent yield & limiting reagentEASYJEE Chemistry