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8 g of sulphur is burnt to form \(\mathrm{SO_2}\) which is oxidised by \(\mathrm{Cl_2}\) water. The solution is treated with \(\mathrm{BaCl_2}\) solut...

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Mole conceptBasic stoichiometry, POAC, percent yield & limiting reagentEASYJEE Chemistry
8 g of sulphur is burnt to form \(\mathrm{SO_2}\) which is oxidised by \(\mathrm{Cl_2}\) water. The solution is treated with \(\mathrm{BaCl_2}\) solution. The amount of \(\mathrm{BaSO_4}\) precipitated is **Options:** - **A.** [object Object] - **B.** [object Object] - **C.** [object Object] - **D.** [object Object] --- **Difficulty:** EASY | **Chapter:** Mole concept | **Topic:** Basic stoichiometry, POAC, percent yield & limiting reagent

Official Solution

## ✅ Correct Answer: **D** ### 📖 Detailed Explanation: This question uses mole concept & stoichiometry. Relate mass, moles and number of particles using the mole concept and basic stoichiometry; doing the algebra gives the value listed in option D. --- *This is an official solution provided by Chem Mantra. For more chemistry questions and solutions, explore our [question bank](/courses).*

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Mole conceptBasic stoichiometry, POAC, percent yield & limiting reagentEASYJEE Chemistry