20 ml of 0.2 M $\mathrm{Al_2SO_4}$ is mixed with 20 ml of 0.6 M $\mathrm{BaCl_2}$ Concentration of $\mathrm{Al_3}$ ion in the solution will be

Question

**Options:**
- **A.** [object Object]
- **B.** [object Object]
- **C.** [object Object]
- **D.** [object Object]

---
**Difficulty:** MEDIUM | **Chapter:** Mole concept | **Topic:** Basic stoichiometry, POAC, percent yield & limiting reagent

Accepted Answer

## ✅ Correct Answer: **A**

### 📖 Detailed Explanation:
This question uses mole concept & stoichiometry. Relate mass, moles and number of particles using the mole concept and basic stoichiometry; doing the algebra gives the value listed in option A.

---
*This is an official solution provided by Chem Mantra. For more chemistry questions and solutions, explore our [question bank](/courses).*

20 ml of 0.2 M \(\mathrm{Al_2SO_4}\) is mixed with 20 ml of 0.6 M \(\mathrm{BaCl_2}\) Concentration of \(\mathrm{Al_3}\) ion in the solution will be

Official Solution

Want More Practice Questions?

Related Topics