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The no. of silver atoms present in a 90% pure silver wire weighing 10 g. is (at.wt. of Ag=108)

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Mole conceptLaw of chemical combination, atomic & molecular mass, mole concept, calculationsMEDIUMJEE Chemistry
The no. of silver atoms present in a 90% pure silver wire weighing 10 g. is (at.wt. of Ag=108) **Options:** - **A.** [object Object] - **B.** [object Object] - **C.** [object Object] - **D.** [object Object] --- **Difficulty:** MEDIUM | **Chapter:** Mole concept | **Topic:** Law of chemical combination, atomic & molecular mass, mole concept, calculations

Official Solution

## ✅ Correct Answer: **C** ### 📖 Detailed Explanation: This question uses atomic structure & atomic mass. Convert all given quantities into moles using n = given amount/molar mass, use Avogadro's number where needed to get particles, and then compare with the options; this matches option C. --- *This is an official solution provided by Chem Mantra. For more chemistry questions and solutions, explore our [question bank](/courses).*

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Mole conceptLaw of chemical combination, atomic & molecular mass, mole concept, calculationsMEDIUMJEE Chemistry